42y^2-y-20=0

Solution for 42y^2-y-20=0 equation:

42y^2-y-20=0

We add all the numbers together, and all the variables

42y^2-1y-20=0

a = 42; b = -1; c = -20;
Δ = b2-4ac
Δ = -12-4·42·(-20)
Δ = 3361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{3361}}{2*42}=\frac{1-\sqrt{3361}}{84}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{3361}}{2*42}=\frac{1+\sqrt{3361}}{84}
$